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  1. Junior Member
    Join Date
    Jan 2005
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    3

    Certifications
    MCSE NT4, var MCP
    #1

    Default Need technique for subnetting,CDIR and VLSM please!

    Hi,
    Would some kind soul help me out with a practical method to working out the subnetting elements for the 70-291 exam? I have a mental block with this stuff , and cannot make any sense out of the resources on the net.
    Does anyone have a good method ?
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  3. Junior Member
    Join Date
    May 2005
    Posts
    9

    Certifications
    MCSE NT4, MCP XP
    #2
    Easiest method would be to convert to binary the IPs to binary. And also use the 128, 64, 32, 16, 8, 4, 2, 1 table and just write it down on top.
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  4. Junior Member
    Join Date
    Feb 2005
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    8

    Certifications
    A+, 70-210, 70-290, 70-291
    #3
    say you have mask of 192.168.1.2/20
    your mask has 20 bits. 255.255.240.0
    2 to the power of the number of masked bits (4) cos thats how many come after the 255.255. -2 = number of subnets
    so (2 to the power of 4) -2 = 14 subnets
    do the same for unmasked bit to find the number of hosts per subnet.
    (2 to the power of twelve -2) -2 = 4094 hosts per subnet.
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  5. Senior Member
    Join Date
    Apr 2005
    Location
    Houston
    Posts
    429

    Certifications
    CCNA; ITIL; MCSA/MCSE 2000/2003:Messaging
    #4
    Theres an old book from exam cram called tcp/ip, it deals with all subnets and understanding them. It was one of those exams that were required for nt4 mcse.

    You can find this book at a second hand book store or e*ay...
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  6. Member
    Join Date
    Aug 2004
    Location
    New York
    Posts
    48

    Certifications
    A+, Net +, MCSA
    #5
    Quote Originally Posted by chris.brown
    say you have mask of 192.168.1.2/20
    your mask has 20 bits. 255.255.240.0
    2 to the power of the number of masked bits (4) cos thats how many come after the 255.255. -2 = number of subnets
    so (2 to the power of 4) -2 = 14 subnets
    do the same for unmasked bit to find the number of hosts per subnet.
    (2 to the power of twelve -2) -2 = 4094 hosts per subnet.
    Thanks, that explained it alot better than my books.

    But once I do that, how do I determine the exact IP addresses to assign for the network?
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