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Thread: Subnet question

  1. Junior Member
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    Sep 2017
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    #1

    Default Subnet question

    Hello all

    Stuck on this problem. plz help

    What is the network address and subnet mask (in CIDR noration) of the hidden (xxx.xxx.xxx.xxx/xx) subnet? The whole network has a network address and subnet mask of 192.168.0.0/23



    The correct answer is:
    192.168.1.128/26
    The block size for a subnet is 256-subnet mask value. Start at zero and count in block sizes. Every block size will be a new network address. Find the block size of the highest subnet and see what the next block will be.


    I am able to understand /26 part but how are they getting the network ID?

    Thanks
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  3. Junior Member Registered Member
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    #2
    Is this a multiple choice? What is the other option? Just to know.
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  4. Member NEODREAM's Avatar
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    Apr 2016
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    #3
    /26 is 255.255.255.192 so your block size is 64, which indicates when each network begins, example:

    192.168.1.0 - .63
    192.168.1.64 - .127
    192.168.1.128 - .191
    192.168.1.192 - .255

    From the way the question is asked I'm still not too sure what they are wanting, but to answer your question that is why the network starts at the .128 for a /26 in this example.
    Currently Working On: B.S. Cybersecurity & Information Assurance
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